An inverted tube barometer is kept on a lift moving downward with a deceleration $\alpha$. The density of mercury is $\rho$ and the acceleration due to gravity is $g$. If the atmospheric pressure is $P_0$,then:

• A
  Height of the mercury column in the lift will be $\frac{P_0}{\rho(g + \alpha)}$
• B
  Height of the mercury column in the lift will be $\frac{P_0}{\rho(g - \alpha)}$
• C
  Height of the mercury column in the lift will be $\frac{P_0}{\rho g}$
• D
  Height of the mercury column in the lift will be $\frac{P_0}{\rho \alpha}$